BANK EXAM

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BANK EXAM Placement Papers

1. The angle between the minute hand and the hour hand of a clock when the time is 4.20, is:
A. 0º
B. 10º
C. 5º
D. 20º

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ANS

ans is b)10 degree
It is 4 hours 20 mins.
Because hour hand moves 30 degree in 1hour.
4:20 = 4 +20/60 = 4+1/3 = 13/3.
So it is 1/3 hours passed so it rotates 10 degree.
Total angle of hours hand is 30*4+10 = 130 degree.

Minute hand moves 6 degree in 1 minute = 20*6 = 120 degree.
So 130-120 = 10 degree.

2. In an exam,it is required to get 65% of marks to pass.a stydent gets 874 marks and is declared failed by 10%marks.what is the maximum aggregate marks a student can get

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ANS:

this is simple method:
65% is the pass marks
let me assume 100 is the max marks
874 marks are declared to the failed of 10% marks
so reduced to 65 to 55 percentage
than 55 marks = 874
100 =?
874*(100/55)=1589.2
100

3. product of two co prime number is 117. their lcm should be

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ANS:

product of two numbers=lcm*hcf
since the nos. are co-prime,their hcf=1
hence,lcm=product of two nos.=117

4. A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, the how old is B?
A. 7
B. 8
C. 9
D. 10
E. 11

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ANS:

ans is option D)10
A=B+2
B=2c => A=2C+2

A+B+C=27

2C+2+2C+C=27

=> 5C=25....==>C=5
So B=2C
B=2(5)=10

5. Naresh has X no of10p coins, twice X of 25p coins and 5 more than 25p is 50p coins.if total money Naresh have os rs.122.5.Find the number of 50p coins?
(a) 150 (b) 140 (c) 155 (d) 120 (5) 100

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ANS:

ans- 155

10x + 25*(2x) + 50*(2x+5)=122.5
x=75
hence 2x+5 = 155

6. A sum of Rs 817 is divided among A, Band C such that 'A' receives 25% more than 'B' and 'B' receives 25% less than 'C'. What is A's share in the amount?

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ANS:

Ans is 228

7. Q. The Average of 5 Consecutive even no A,B,C,D,E is 52. What is the Product of B & E ?
Option
a) 2912
b) 2688
c) 3024
d) 2800
e) None of these

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ANS:
ans is option d)2800

average of 5 consecutive even number is 52
52 is the middle number
A B C D E
48 50 52 54 56

product of B&E =50*56 == 2800

8. if 5% more is gained by selling an article for rs. 350 then by selling it for rs. 340 the cost of article is.

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ANS:

Rs 200

Let the cost of article be x

when SP = 350
P% = (350-x)/x*100

when SP = 340
P% = (340-x)/x*100

5% more is gained by selling article for rs. 350 than for 340

(350-x)/x - (340-x)/x = 5/100
10/x = 5/100
x = 200

OR

Alternately

5% more is gained by selling an article for Rs 350 than by selling it for Rs 340
Additional Gain = 350−340 = Rs 10
i.e Rs 10 = 5 % of the cost of the article
Hence Cost of article = 10×100/5 = Rs200

9. Q. The sum of 8 consecutive odd number is 656.Also average of four consecutive even no is 87.what is the sum of the smallest odd number and second largest even number?
Option
1) 165
2) 175
3) 163
4) Cannot be determined
5) None of these

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ANS:
sum of 8 no.is=656
so avg= 656/8=82
s0. no. are 75,77,79,81,83,85,87,89
avg of even no. is=87
so no. are 84,86,88,90
o sum=75+88=163

10. A motor starts with the speed of 70 Km/hr with its speed increasing every two hours by 10 Kmph.In how many hours it will cover 345 kms ?

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ANS:

In 4 hours and 30 minutes it will cover 345kms.

In 1st hour, it finishes = 70km (At the speed of 70km/hr)
In 2nd hour, it finishes = 140km (At the speed of 70km/hr)
Now, after 2 hours it increase speed rate from 70km/hr to 80km/hr.

In 3rd hour, it finishes = 220km (speed of 80km/hr)
In 4th hour, it finishes = 300km (speed of 8okm/hr)
Now, after 2 hours it increase speed rate from 80km/hr to 90km/hr.
Per hour = 90km speed means,
Half n hour = 90/2km => 45km speed.

So, in 4hours 30minutes, it cover 345kms.

11. STATEMENTS---ALL CARS ARE VEHICLES
SOME VEHICLES ARE TRUCKS
CONCLUSIONS--- ALL VEHICLES ARE BEING CARS IS A POSSIBILITY
NO TRUCK IS A CAR

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ANS:

both are not possible i think

12. A library has an average of 510 visitors on Sundays and 240 on other days. The average number of visitors per day in a month of 30 days beginning with a Sunday is:
A. 250
B. 276
C. 280
D. 285

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ANS:

D. 285

Explaination : Average of Visitors in Sunday, X = 510
Average of Visitors in Weekdays, Y = 240
Average of Visitors in a month of 30days, Z = ?
If the Month starts with Sunday means, it have 5 sundays and 25 week days.
Therefore, Z = (5X + 25Y)/30
(i.e) 5X = 5(510)
= 2550
24X = 24(240)
= 5760
Z = (2550+5760)/30   = 8310/30 = 285

13. The difference between the length and breadth of a rectangle is 23 m. If its perimeter is 206 m, then its area is:
A.
1520 m2
B.
2420 m2
C.
2480 m2
D.
2520 m2

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ANS
Let l=x,b=y
x-y=23m
2(x+y)=206m
find the value of x and y.....
x=63 and y=40
area=63*40=2520

14. 3 men or 8 boys can do a piece of work in 17 days.how many days will 2 men and 6 boys together take to finish the same work.plz give a soln

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ANS:

3M=8B=17 d
2M=6B=? ==>(2/3)+(6/8)=17/12 M

3M=17 d
(17/12)M=? ==(3*17*12)/17= 36/3 =12 days

15. Q. A school has enough food for 400 children for 12 days. How long will the food last if 80 more children join them?
Option
(a) 6 days
(b) 7 days
(c) 10 days
(d) 8 days

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ANS:

ans is opt c) 10 days

400 c=12 d
480 c=? ==(400*12)/480 = 10 days

16. A man took loan from a bank at the rate of 12% p.a. simple interest. After 3 years he had to pay Rs. 5400 interest only for the period. The principal amount borrowed by him was:
A.
Rs. 2000
B.
Rs. 10,000
C.
Rs. 15,000
D.
Rs. 20,000

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ANS

SI=(p*n*r)/100
principal amount p=(SI*100)/(n*r)
=(5400*100)/(3*12)
=15000
So ans opt c)Rs.15,000

17. The sum of two number is 25 and their difference is 13. Find their product.
A.
104
B.
114
C.
315
D.
325

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ANS:

x+y = 25
x-y = 13
solve it
x = 19 and y = 6
x*y = 19* 6 =114

18. What will be the least number which when doubled will be exactly divisible by 12, 18, 21 and 30 ?
A. 196
B. 630
C. 1260
D. 2520

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ANS:

ANSWER : 630

SOLUTION :

LCM of 12,18,21 and 30 is 1260
So required number is 1260/2 = 630

19. Q. In a coded language
If AUDIO = 85
VIDEO = 80
Then
RADIO = ?

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ANS:

ans:- 88

Logic is simple. Take opposite letter for every letter and sum all that numbers.

For AUDIO opposite word is ZFWRL= 26+6+23+18+12=85
For VIDEO opposite word is ERWVL= 5+18+23+22+12=80

for RADIO opposite word is IZWRL= 9+26+23+18+12= 88

20. Anna left for the city A from city B at 5.20 a.m. She travelled at the speed of 80 kmph for hours 15 min. After that the speed was reduced to 60 kmph. If the distance between the two cities is 350 km, at what time did Anna reach City A?
Option
1) 9.20 am
2) 9.25 am
3) 9.35 am
4) 10.05 am
5) None of these

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ANS:

5) None of these

Distance traveled with speed of 80 kmph= (1/4)80= 20 km.
Remaining distance=350-20=330 km.
Time taken to travel 330 km @60 kmph= 330/60 =33/6=5 1/2 hours.
Total time of the journey= (1/4)+(33/6)=69/12 =5 3/4 Hr.=5 Hrs 45 min.
Anna will reach to city A at time=5:20+5:45=11:05 a.m.



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