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English: synonyms(3),antonyms(2), passages(2), fill in d blanks
Aptitude: compound n simple interest,probability, permutation, speed n distance, number system, profit n loss.
Logical reasoning: blood relation,order of words, 2 small passages, coding n decoding
English: synonyms(3),antonyms(2), passages(2), fill in d blanks
Aptitude: compound n simple interest,probability, permutation, speed n distance, number system, profit n loss.
Logical reasoning: blood relation,order of words, 2 small passages, coding n decoding
1. Statements: All mobiles
are androids.
No android is a phone.
Conclusions: I. Some mobiles are not phones.
II. No phone is a mobile
2) If only conclusion II follows.
3) If either conclusion I or II follows.
4) If neither conclusion I nor II follows.
5) If both conclusions I and II follow.
ANS: (3) If either conclusion I or II follows
is the right answer
No android is a phone.
Conclusions: I. Some mobiles are not phones.
II. No phone is a mobile
2) If only conclusion II follows.
3) If either conclusion I or II follows.
4) If neither conclusion I nor II follows.
5) If both conclusions I and II follow.
ANS: (3) If either conclusion I or II follows
is the right answer
2. Five farmers have 7,9,11,13 & 14 apple trees respectively in their orchards.last year each of them discovered that every tree in their own orchard bore exactly d same no of apples.further,if d 3rd farmer gives one apple to the 1st,& the 5th gives 3 to each of the 2nd & d 4th,they would all exactly have the same no of apples, what were d yields per tree in the orchards of d 3rd & 4th farmers?
ANS:
11,9
Let the number of apples in each tree of the 5 farmers be a, b, c, d,e respectively. Therefore total no of apples are 7a, 9b, 11c, 13d and 14e respectively.
Given,
7a+1 = 9b+3 = 11c-1 = 13d+3 = 14e-6 = x
9b+3 = 13d+3
===> 9b = 13d
so take b = 13 and d = 9
9b+3 = 9*13+3 = 120
ie, x=120
substituting
7a+1 = 120
7a = 119
a = 17
11c-1 = 120
11c = 121
c=11
14e-6 = 120
14e = 126
e = 9
Yields per tree in the orchards of d 3rd & 4th farmers= 11,9
Let the number of apples in each tree of the 5 farmers be a, b, c, d,e respectively. Therefore total no of apples are 7a, 9b, 11c, 13d and 14e respectively.
Given,
7a+1 = 9b+3 = 11c-1 = 13d+3 = 14e-6 = x
9b+3 = 13d+3
===> 9b = 13d
so take b = 13 and d = 9
9b+3 = 9*13+3 = 120
ie, x=120
substituting
7a+1 = 120
7a = 119
a = 17
11c-1 = 120
11c = 121
c=11
14e-6 = 120
14e = 126
e = 9
Yields per tree in the orchards of d 3rd & 4th farmers= 11,9
3. if P is father of R,and R is not son of
P,M is spouse of R then how P related to M?
ANS
Father-in-law
P-->father of R
R--->daughter of P
M--->husband of R
P-->father of R
R--->daughter of P
M--->husband of R
4. Am going to do my higher studies ____ USA.
a)in a
b)in the
c)into
d)by
e)through
ANS
(b) ll be the answer
5. It_____ have been my show.
a)should
b)would
c)could
d)not
a)should
b)would
c)could
d)not
ANS”: (c)
could have been my show
6. Solve
(x-a)*(x-b)*(x-c)*...........(x-z)=?
(x-a)*(x-b)*(x-c)*...........(x-z)=?
ANS”:
(x-a)*(x-b)*(x-c)*...........(x-z)
= (x-a)*(x-b)*(x-c)*...........(x-x)*(x-y)*(x-z)
since (x-x)=0 so, whole product is zero
(x-a)*(x-b)*(x-c)*...........(x-z )= 0
= (x-a)*(x-b)*(x-c)*...........(x-x)*(x-y)*(x-z)
since (x-x)=0 so, whole product is zero
(x-a)*(x-b)*(x-c)*...........(x-z )= 0
7. 2^81 when divided by 6,what is the remainder
ANS:
2^81/6 ====> (2^1*2^2*2^3*....81 times]/6
2^1/6 ----------> remainder=2
2^2/6 -->4/6 ---> remainder=4
2^3/6 -->8/6 ---> remainder=2
2^4/6 -->16/6 --->remainder=4
2^5/6 -->32/6 --->remainder=2
.
.
.
it goes on in a cyclic manner
so remainder is "2" for all odd powers of 2 nd "4" for all even powers of 2
here 2^81 which has the odd power
so remainder =2
2^1/6 ----------> remainder=2
2^2/6 -->4/6 ---> remainder=4
2^3/6 -->8/6 ---> remainder=2
2^4/6 -->16/6 --->remainder=4
2^5/6 -->32/6 --->remainder=2
.
.
.
it goes on in a cyclic manner
so remainder is "2" for all odd powers of 2 nd "4" for all even powers of 2
here 2^81 which has the odd power
so remainder =2
8. Eight friends P,Q,R,S,T,U,V And W go to a hotel to
celebrate the birthday party, they all like different dishes viz. dosa, idli,
momos, burger, pizza, kothe, parantha and bhatura.they are sitting around a
circular table facing the center such that one person is sitting opposite to
another personU does not like Burger but sits opposite to the person, who is
near to the person, who like Dosa. The person who likes Parantha sits fourth to
the left of the person, who is immediate right of H. Q sits third to the left
of the person, who likes Idli. The person who likes Momos is Neither near the
person, who likes Dosa nor opposite to Q. The person who likes Pizza is
opposite to W, who is not near to the person who likes Dosa. U sits on the
third place from the person who likes Momos. Person who likes Burger is on
second place from the person who likes Idli and opposite to the person, who is
immediate to the left of S. P is opposite of U but not near Q. The person who
likes Kothe is opposite to T and they are not near to V. the person who likes
Parantha is third to the right of PHow many friends are sitting between the
person, who likes Kothe and the person who likes Bhatura?
ANS : 1 friend. there is some
problem in the question as eight friends mentioned are p,q,r,s,t,u,v,w but in
problem 6th line has "H"
9.
antonyms
setteled*
archaic*
prankish*
setteled*
archaic*
prankish*
ANS: settled
- unsettled
archaic-modern
prankish-sober,serious
archaic-modern
prankish-sober,serious
10. synonym
for Faux pas and Emanate
ANS emanate-emit,coming from a source
Faux pas-blunder,a social error.
Faux-means false
Pas-means step
Faux pas-blunder,a social error.
Faux-means false
Pas-means step
11. the simple absence of grief and indiguation at our national tragedy can be termed as________
a)acceptance
b)concurrence
c)credence
d)abdiction
ANS:
d)abdication
12.
find the odd one
cde
pqr
tuv
mno
pqr
tuv
mno
ANS: Sequence is maintained in all the four options. The only
point through which one can be called odd is the presence of a vowel in it.
cde-vowel 'e'
pqr-no vowel
tuv-vowel 'u'
mno-vowel 'o'
So, the odd one is pqr
cde-vowel 'e'
pqr-no vowel
tuv-vowel 'u'
mno-vowel 'o'
So, the odd one is pqr
13. find the odd one
adg
hkn
psw
mps
hkn
psw
mps
ANS: psw
since difference between each characters in every word is 3, but psw doesnt follow this
adg - 147 ==>( 4-1=3, 7-4=3)
hkn - 8,11,14 ==> (11-8=3, 14-11=3 )
mps - 13,16, 19 ( 16-13 =3 , 19-16= 3)
psw - 16, 19, 23 ==> (19-16=3 , 23-19= 4)
Hence ans : psw
14. find the odd one
since difference between each characters in every word is 3, but psw doesnt follow this
adg - 147 ==>( 4-1=3, 7-4=3)
hkn - 8,11,14 ==> (11-8=3, 14-11=3 )
mps - 13,16, 19 ( 16-13 =3 , 19-16= 3)
psw - 16, 19, 23 ==> (19-16=3 , 23-19= 4)
Hence ans : psw
14. find the odd one
adp
qtx
hkr
ste
qtx
hkr
ste
ANS: I guess its ste
adp -- 1,4,16 {1+4+16= 21}
qtx -- 17,20,24 {17+20+24= 61}
hkr -- 8,11,18 {8+11+18=37}
ste -- 19,20,5 {19+20+5 = 44}
except "ste" ,other words produce even results
So ans : ste
adp -- 1,4,16 {1+4+16= 21}
qtx -- 17,20,24 {17+20+24= 61}
hkr -- 8,11,18 {8+11+18=37}
ste -- 19,20,5 {19+20+5 = 44}
except "ste" ,other words produce even results
So ans : ste
15. Diamonds value is proportional to its weight. when diamonds broke into pieces in ratio 1:2:3:4:5 total loss in value is 85000. what is the value of the diamond twice the weight of original diamond.
ANS ;
There
will be no loss.
2 (x+2x+3x+4x+5x)=85000 =>x=8500/3
Now it said that value of the diamond is twice the Weight of original diamond therefore,
Value = 2 (x)+2 (2x)+2 (3x)+2 (4x)+2 (5x) = 30x
Then, 30*(8500/3) = 85000.
Therefore their is no loss.
value= (weight)^2
But if you take value of diamond is square of its weight then we will have loss of 74000.
2 (x+2x+3x+4x+5x)=85000 =>x=8500/3
Now it said that value of the diamond is twice the Weight of original diamond therefore,
Value = 2 (x)+2 (2x)+2 (3x)+2 (4x)+2 (5x) = 30x
Then, 30*(8500/3) = 85000.
Therefore their is no loss.
value= (weight)^2
But if you take value of diamond is square of its weight then we will have loss of 74000.
16. Diamond\s value is proportional to its weight 2 .When the diamond broke what of pieces in ratio 1:2:3;4:5. Total loss in value is 85,000. What is the value of the diamond twice the wt of the original diamond.
ANS:
let
weight of the original diamond be 15k ( This number is the sum of the numbers
in the ratio given ) ,so, it's value would be 225k^2. Now, the broken diamond's
value adds upto 55k^2(. So, loss of value is 170k^2 which is 85,000. [85,000/170] This gives k^2 =
500.
We need (30k)^2 = 900k^2 = 900* 500 = 450,000
We need (30k)^2 = 900k^2 = 900* 500 = 450,000
from
where this 55k^2 come??
add the square of ratios u will get 55k^2...1+4+9+16+25=55
17. emblem is coded as 216;
crude is coded as 125
Cricket will be ?
ANS; coding
follows (no. of letters)^3
emblem = 216 = 6^3
crude = 125 = 5^3
Cricket = 7^3 =343
emblem = 216 = 6^3
crude = 125 = 5^3
Cricket = 7^3 =343
18. Q. Like TABLET = BATTLE. So the answer
is: FIGHT
1. RUGGED
a) resentment
b) fight
c) help
d) monster
2. GORE
a) resentment
b) fight
c) help
d) monster
3. STASSI
a) resentment
b) fight
c) help
d) monster
4. ENFOLD
a) cuddle
b) sleeping
c) proclamination
d) ointment
5. LAMB
a) cuddle
b) sleeping
c) proclamination
d) ointment
6. RECEDE
a) cuddle
b) sleeping
c) proclamination
d) ointment
7. PLEASE
a) cuddle
b) sleeping
c) proclamination
d) ointment
1. RUGGED
a) resentment
b) fight
c) help
d) monster
2. GORE
a) resentment
b) fight
c) help
d) monster
3. STASSI
a) resentment
b) fight
c) help
d) monster
4. ENFOLD
a) cuddle
b) sleeping
c) proclamination
d) ointment
5. LAMB
a) cuddle
b) sleeping
c) proclamination
d) ointment
6. RECEDE
a) cuddle
b) sleeping
c) proclamination
d) ointment
7. PLEASE
a) cuddle
b) sleeping
c) proclamination
d) ointment
ANS
GRUGED :
Resentment
OGRE : Monster
ASSIST : Help
OGRE : Monster
ASSIST : Help
ENFOLD : Cuddle
BALM : Ointment
DECREE : Proclamation
RUGGED-->GRUDGE = RESENTMENT
GORE--->OGRE = MONSTER
ASSIST=HELP
BALM=OINTMENT
DECREE=PROCLAMINATION
ASLEEP=SLEEPING
ENFOLD=CUDDLE
19. 8 people A,B,C,D,E,F,G and H, lives in 4
storied building which contains 2 flats each. Flats number 7 and 8 belongs to
4th floor from left to right. Flats 3 and 4 are the second floor from the
bottom and are numbered right to left. So are 5 and 6 which lies on second
floor from top. 1 and 2 are the first floors numbered left to right. A and E
stays on the second floor from the bottom. F lies one floor above B, which is
one floor above C
ANS
if we
consider 4 stairs __7_______8__
__5_______6__ F
__4_______3__ A and E lives in 2nd floor
__1_______2__ B C
__5_______6__ F
__4_______3__ A and E lives in 2nd floor
__1_______2__ B C
20. 79, 64 ,
26, 15 ?
ANS
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